千分位输出 1,233,232格式

xiaoyu9805119

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1^# xiaoyu9805119 发表于 2009-01-14 09:39

千分位输出 1,233,232格式

摘抄自邮件列表，我的方法比较土，小数点也没有加进去，locale未尽测试。
邮件收录在：http://wiki.woodpecker.org.cn/moin/MiscItems/2009-01-13

最新方法：
>>> while True:
...    (s,count) = re.subn(r"(\d)(\d{3})((:?,\d\d\d)*)$",r"\1,\2\3",s)
...    if count == 0 : break

locale
国外同志们有遇到同样的问题。看这里：
http://bytes.com/groups/python/454763-number-format-function
其中有个回帖是这样的。
This is a little faster:
def number_format(num, places=0):

"""Format a number according to locality and given places"""
locale.setlocale(locale.LC_ALL, "")
return locale.format("%.*f", (places, num), True)

I tested this ok with my test

再一例
eric <pony.ch@gmail.com>
reply-to       python-cn@googlegroups.com
to    python-cn`CPyUG`华蟒用户组 <python-cn@googlegroups.com>
date Tue, Jan 13, 2009 at 16:53
subject [CPyUG:76807] Re: python怎么输出1,233,232这种形式？

http://www.jaharmi.com/2008/05/2 ... ython_locale_module

>>> import locale
>>> a = {'size': 123456789, 'unit': 'bytes'}
>>> print(locale.format("%(size).2f", a, 1))
123456789.00
>>> locale.setlocale(locale.LC_ALL, '') # Set the locale for your system
'en_US.UTF-8'
>>> print(locale.format("%(size).2f", a, 1))
123,456,789.00

DIY
smallfish <smallfish@live.cn>
reply-to       python-cn@googlegroups.com
to    python-cn@googlegroups.com
date Tue, Jan 13, 2009 at 16:53
subject [CPyUG:76806] Re: python怎么输出1,233,232这种形式？

我试了一个土方法：

>>> s = "1234567890"
>>> s = s[::-1]
>>> a = [s[i:i+3] for i in range(0,len(s),3)]
>>> print (",".join(a))[::-1]

--------------------------------------------------------------------------------

其实用perl实现感觉更简单了些：
$size = "1234567890";
1 while $size =~ s/(\d)(\d{3})((:?,\d\d\d)*)$/$1,$2$3/;
print $size, "\n";