fsocket 返回status问题

提交资料到指定的网址
"/checking/"下有index.php echo "success"

"/checking/" 成功返回HTTP/1.1 200
"/checking" 返回HTTP/1.1 301 

伺服器是Apache的，可以不用“/”也返回200吗

PHP code

$host = "127.0.0.1";
$port = 8088;
$script = "/checking/";

$request = "";
$request .= "username=testing&";
$request .= "password=123456";

//build header
$header = "POST $script HTTP/1.1\r\n";
$header .= "Host: $host\r\n";
$header .= "Content-Type: application/x-www-form-urlencoded\r\n";
$header .= "Content-length: ".strlen($request)."\r\n";
$header .= "Connection: close\r\n\r\n";

$debug.="Host: ".$host."<br />";
$debug.="Port: ".$port."<br />";
$debug.="Requset: ".$request."<br />";

$socket = fsockopen($host, $port, $errno, $errstr, 30);
$output=array();
if($socket){
    fputs($socket, $header.$request);
    $debug.="Response: ";
    while(!feof($socket)){
        $data=fgets($socket);
        $debug.=$data;
    }
echo $debug;
    fclose($socket);
}
}

可以,那你就用这种方法
$host = "127.0.0.1";
$port = 8088;
$script = "/checking/index.php";