PHP 调用webservice返回结果里带有头信息怎么获取里面的xml

下面是请求后返回的数据
如何获取其中的xml

HTTP/1.1 200 OK
Connection: close
Date: Fri, 27 May 2011 02:38:56 GMT
Server: Microsoft-IIS/6.0
X-Powered-By: ASP.NET
X-AspNet-Version: 2.0.50727
Cache-Control: private, max-age=0
Content-Type: text/xml; charset=utf-8
Content-Length: 457

<?xml version="1.0" encoding="utf-8"?><soap:Envelope xmlns:soap="http://schemas.xmlsoap.org/soap/envelope/" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema"><soap:Body><SubmitMmsResponse xmlns="http://MmsWebInterface.org/"><SubmitMmsResult><State>0</State><MsgID>110527103856160</MsgID><MsgState>审查</MsgState><Reserve>199702000</Reserve></SubmitMmsResult></SubmitMmsResponse></soap:Body></soap:Envelope>

作者: ck52110u 发布时间: 2011-05-27

假设返回数据的文件为：b.php ,在c.php中获取：

作者: jordan102 发布时间: 2011-05-27

LS可以清楚点吗没太明白为什么要去c里获取？

作者: ck52110u 发布时间: 2011-05-27

不好意思，点错了，接着上面：
PHP code


       $con=file_get_contents('b.php');
       preg_match("/<\?xml[^>]+>(.*)<\/soap:Envelope>/is",$con,$arr);
       echo $arr[0];

输出：
<?xml version="1.0" encoding="utf-8"?><soap:Envelope xmlns:soap="http://schemas.xmlsoap.org/soap/envelope/" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema"><soap:Body><SubmitMmsResponse xmlns="http://MmsWebInterface.org/"><SubmitMmsResult><State& gt;0</State><MsgID>110527103856160< /MsgID><MsgState>审查< /MsgState><Reserve>199702000</Reserve></SubmitMmsResult></SubmitMmsResponse></soap:Body></soap:Envelope>

作者: jordan102 发布时间: 2011-05-27

PHP code

 
$flg=0;

$str_xml="";
while ($line = fgets($fp)) {

        if (ereg("^\<\?xml",$line)) {
        $flg=1;
    }
    if($flg){
      $str_xml.=$line;
     }
}

作者: yaoxin125 发布时间: 2011-05-27

也可以在写在一个文件里：
PHP code


   $str=<<<HTML
HTTP/1.1 200 OK
Connection: close
Date: Fri, 27 May 2011 02:38:56 GMT
Server: Microsoft-IIS/6.0
X-Powered-By: ASP.NET
X-AspNet-Version: 2.0.50727
Cache-Control: private, max-age=0
Content-Type: text/xml; charset=utf-8
Content-Length: 457

<?xml version="1.0" encoding="utf-8"?><soap:Envelope xmlns:soap="http://schemas.xmlsoap.org/soap/envelope/" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema"><soap:Body><SubmitMmsResponse xmlns="http://MmsWebInterface.org/"><SubmitMmsResult><State& gt;0</State><MsgID>110527103856160< /MsgID><MsgState>审查< /MsgState><Reserve>199702000</Reserve></SubmitMmsResult></SubmitMmsResponse></soap:Body></soap:Envelope>  
HTML;

 preg_match("/<\?xml[^>]+>(.*)<\/soap:Envelope>/is",$str,$arr);
 echo $arr[0];

作者: jordan102 发布时间: 2011-05-27

谢谢两位明白了！！！

作者: ck52110u 发布时间: 2011-05-27

不懂路过帮顶

作者: XmlRequest 发布时间: 2011-05-27

PHP 调用webservice返回结果里带有头信息怎么获取里面的xml

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