grep命令抓取问题

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如图所示！使用命令输出成功和失败两种信息！
我只想让它显示成功信息用grep抓关键字 'succeeded!'
结果是：跟上图一样！

[code][root@localhost python]# nc -v -z -w2 192.168.1.203 1-21|grep 'succeeded!'
nc: connect to 192.168.1.203 port 13 (tcp) failed: Connection refused
nc: connect to 192.168.1.203 port 14 (tcp) failed: Connection refused
nc: connect to 192.168.1.203 port 15 (tcp) failed: Connection refused
nc: connect to 192.168.1.203 port 16 (tcp) failed: Connection refused
nc: connect to 192.168.1.203 port 17 (tcp) failed: Connection refused
nc: connect to 192.168.1.203 port 18 (tcp) failed: Connection refused
nc: connect to 192.168.1.203 port 19 (tcp) failed: Connection refused
nc: connect to 192.168.1.203 port 20 (tcp) failed: Connection refused
Connection to 192.168.1.203 21 port [tcp/ftp] succeeded!

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[/code]
反过来选择，我忽略refused
结果：还是一样！真是奇了个怪了。

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作者: skyxue215 发布时间: 2011-03-09

那个是 “标准错误输出”stderr 输出的。

作者: jerryjzm 发布时间: 2011-03-09

回复 jerryjzm

谢了兄弟

作者: skyxue215 发布时间: 2011-03-09